2(2x^2-25X+68)=0

Solution for 2(2x^2-25X+68)=0 equation:

2(2x^2-25x+68)=0

We multiply parentheses

4x^2-50x+136=0

a = 4; b = -50; c = +136;
Δ = b2-4ac
Δ = -502-4·4·136
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-18}{2*4}=\frac{32}{8}
=4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+18}{2*4}=\frac{68}{8}
=8+1/2
$